What are the solutions to the equation 4x^2+6=9 ?

The solutions to the equation 4x^2+6=9 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2

Find the zeros of 4x^2+6=9

The zeros of 4x^2+6=9 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2

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4 x^{2} + 6 = 9

x = \frac{3}{2}, x = - \frac{3}{2}

Solution steps

4 x^{2} + 6 = 9

Move

6

to the right side

4 x^{2} = 3

Divide both sides by

4

x^{2} = \frac{3}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{4}, x = - \frac{3}{4}

\frac{3}{4} = \frac{3}{2}

- \frac{3}{4} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

- 0.2 (x + 22) (x - 15) = 0

2 x - 10 \geq \frac{1}{8} (16 x + 32)

0.078 x^{2} + 0.052 x - 1 = 0

5 x - 2 < 18 and - 2 x < - 4

What are the solutions to the equation 4x^2+6=9 ?
The solutions to the equation 4x^2+6=9 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2
Find the zeros of 4x^2+6=9
The zeros of 4x^2+6=9 are x=(sqrt(3))/2 ,x=-(sqrt(3))/2