en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x-10>= 1/8 (16x+32)

Solution

2 x - 10 \geq \frac{1}{8} (16 x + 32)

Solution

No Solution

Solution steps

2 x - 10 \geq \frac{1}{8} (16 x + 32)

Expand

\frac{1}{8} (16 x + 32) : 2 x + 4

2 x - 10 \geq 2 x + 4

Move

10

to the right side

2 x \geq 2 x + 14

Move

2 x

to the left side

0 \geq 14

Therefore, the solution is

No Solution

Popular Examples

0.078x^2+0.052x-1=0

0.078 x^{2} + 0.052 x - 1 = 0

simplify (\sqrt[3]{x^5})/(\sqrt[3]{y^4)}simplify

5x-2<18\land-2x<-4

5 x - 2 < 18 and - 2 x < - 4

a=sqrt(1^2+\sqrt{2)}

a = 1^{2} + 2

x^{2} - 3 x + 2 = 2.1

Frequently Asked Questions (FAQ)

What is 2x-10>= 1/8 (16x+32) ?
The solution to 2x-10>= 1/8 (16x+32) is No Solution