What are the solutions to the equation x^2-3x+2=2.1 ?

The solutions to the equation x^2-3x+2=2.1 are x=(15+sqrt(235))/(10),x=(15-sqrt(235))/(10)

Find the zeros of x^2-3x+2=2.1

The zeros of x^2-3x+2=2.1 are x=(15+sqrt(235))/(10),x=(15-sqrt(235))/(10)

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x^{2} - 3 x + 2 = 2.1

x = \frac{15 + 235}{10}, x = \frac{15 - 235}{10}

Decimal Notation

x = 3.03297 \dots, x = - 0.03297 \dots

Solution steps

x^{2} - 3 x + 2 = 2.1

Multiply both sides by

10

10 x^{2} - 30 x + 20 = 21

Move

21

to the left side

10 x^{2} - 30 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 10 ( - 1 )}{2 \cdot 10}

(- 30)^{2} - 4 \cdot 10 (- 1) = 2235

x_{1, 2} = \frac{- ( - 30 ) \pm 2 235}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 2 235}{2 \cdot 10}, x_{2} = \frac{- ( - 30 ) - 2 235}{2 \cdot 10}

x = \frac{- ( - 30 ) + 2 235}{2 \cdot 10} : \frac{15 + 235}{10}

x = \frac{- ( - 30 ) - 2 235}{2 \cdot 10} : \frac{15 - 235}{10}

The solutions to the quadratic equation are:

x = \frac{15 + 235}{10}, x = \frac{15 - 235}{10}

\frac{5}{8} - \frac{3}{4}

5 s^{3} - 135 d^{3}

\frac{b - a}{a - b}

(x - 2) (x + 2) (x + 1) - 4 (x + 2)

\frac{1}{2} (\frac{3}{2})

What are the solutions to the equation x^2-3x+2=2.1 ?
The solutions to the equation x^2-3x+2=2.1 are x=(15+sqrt(235))/(10),x=(15-sqrt(235))/(10)
Find the zeros of x^2-3x+2=2.1
The zeros of x^2-3x+2=2.1 are x=(15+sqrt(235))/(10),x=(15-sqrt(235))/(10)