What is the answer to solvefor m,sqrt(2m+3)=n ?

The answer to solvefor m,sqrt(2m+3)=n is m=(n^2-3)/2 {n>= 0}

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solvefor m,sqrt(2m+3)=n

solve for

m, 2 m + 3 = n

m = \frac{n ^{2} - 3}{2} {n \geq 0}

Solution steps

2 m + 3 = n

Square both sides:

2 m + 3 = n^{2}

2 m + 3 = n^{2}

Solve

2 m + 3 = n^{2} : m = \frac{n ^{2} - 3}{2}

m = \frac{n ^{2} - 3}{2}

Verify Solutions:

m = \frac{n ^{2} - 3}{2} {n \geq 0}

The solution is

m = \frac{n ^{2} - 3}{2} {n \geq 0}

6 x - 1 = 9

x - 5 - x - 8 = 3

1 - x = 0

2 x = 9 x - 9

2 + x - 2 - x = x

What is the answer to solvefor m,sqrt(2m+3)=n ?
The answer to solvefor m,sqrt(2m+3)=n is m=(n^2-3)/2 {n>= 0}