What is the answer to x^2+4x+3=sqrt(x^2+4x+5) ?

The answer to x^2+4x+3=sqrt(x^2+4x+5) is x=-2+sqrt(3),x=-2-sqrt(3)

Solve for x: x^2+4x+3=sqrt(x^2+4x+5)

The solution is x=-2+sqrt(3),x=-2-sqrt(3)

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x^{2} + 4 x + 3 = x^{2} + 4 x + 5

x = - 2 + 3, x = - 2 - 3

Decimal Notation

x = - 0.26794 \dots, x = - 3.73205 \dots

Solution steps

x^{2} + 4 x + 3 = x^{2} + 4 x + 5

Square both sides:

x^{4} + 8 x^{3} + 22 x^{2} + 24 x + 9 = x^{2} + 4 x + 5

x^{4} + 8 x^{3} + 22 x^{2} + 24 x + 9 = x^{2} + 4 x + 5

Solve

x^{4} + 8 x^{3} + 22 x^{2} + 24 x + 9 = x^{2} + 4 x + 5 : x = - 2, x = - 2 + 3, x = - 2 - 3

x = - 2, x = - 2 + 3, x = - 2 - 3

Verify Solutions:

x = - 2

False

, x = - 2 + 3

True

, x = - 2 - 3

True

The solutions are

x = - 2 + 3, x = - 2 - 3

3 x - 5 = 2

3 x - 5 = 7

2 x - x + 1 = 1

2 x + 1^{2} = x^{2}

A, U = n A - r

What is the answer to x^2+4x+3=sqrt(x^2+4x+5) ?
The answer to x^2+4x+3=sqrt(x^2+4x+5) is x=-2+sqrt(3),x=-2-sqrt(3)
Solve for x: x^2+4x+3=sqrt(x^2+4x+5)
The solution is x=-2+sqrt(3),x=-2-sqrt(3)