What is the answer to sqrt(3x^2-3)=x+1 ?

The answer to sqrt(3x^2-3)=x+1 is x=-1,x=2

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sqrt(3x^2-3)=x+1

3 x^{2} - 3 = x + 1

x = - 1, x = 2

Solution steps

3 x^{2} - 3 = x + 1

Square both sides:

3 x^{2} - 3 = x^{2} + 2 x + 1

3 x^{2} - 3 = x^{2} + 2 x + 1

Solve

3 x^{2} - 3 = x^{2} + 2 x + 1 : x = - 1, x = 2

x = - 1, x = 2

Verify Solutions:

x = - 1

True

, x = 2

True

The solutions are

x = - 1, x = 2

t + 1 = t + 9

x^{\frac{1}{3}} = \frac{1}{3}

7 x + 1 = 2 x - 4

x^{2} - 9 = x + 11

What is the answer to sqrt(3x^2-3)=x+1 ?
The answer to sqrt(3x^2-3)=x+1 is x=-1,x=2
Solve for x: sqrt(3x^2-3)=x+1
The solution is x=-1,x=2