What is the answer to sqrt(x+1)-\sqrt[3]{x}=1 ?

The answer to sqrt(x+1)-\sqrt[3]{x}=1 is x=0,x=-1,x=8

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sqrt(x+1)-\sqrt[3]{x}=1

x = 0, x = - 1, x = 8

Solution steps

Rewrite the equation with

u^{3} + 1 - u = 1

Solve

u^{3} + 1 - u = 1 : u = 0, u = - 1, u = 2

u = 0, u = - 1, u = 2

Substitute back

solve for

x

Solve

x = 0, x = - 1, x = 8

Verify Solutions:

x = 0

True

, x = - 1

True

, x = 8

True

The solutions are

x = 0, x = - 1, x = 8

x^{\frac{1}{3}} = \frac{1}{3}

7 x + 1 = 2 x - 4

x^{2} - 9 = x + 11

x, x + y = 0

2 x + 9 - x + 1 = 2

What is the answer to sqrt(x+1)-\sqrt[3]{x}=1 ?
The answer to sqrt(x+1)-\sqrt[3]{x}=1 is x=0,x=-1,x=8
Solve for x: sqrt(x+1)-\sqrt[3]{x}=1
The solution is x=0,x=-1,x=8