What is the answer to 1+sqrt(x)=sqrt(1+x^2) ?

The answer to 1+sqrt(x)=sqrt(1+x^2) is x=0,x\approx 2.31459…

Solve for x: 1+sqrt(x)=sqrt(1+x^2)

The solution is x=0,x\approx 2.31459…

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1 + x = 1 + x^{2}

x = 0, x \approx 2.31459 \dots

Solution steps

1 + x = 1 + x^{2}

Remove square roots

4 x = x^{4} - 2 x^{3} + x^{2}

Solve

4 x = x^{4} - 2 x^{3} + x^{2} : x = 0, x \approx 2.31459 \dots

x = 0, x \approx 2.31459 \dots

Verify Solutions:

x = 0

True

, x \approx 2.31459 \dots

True

The solutions are

x = 0, x \approx 2.31459 \dots

2 x - 5 - 3 = 3

2 x - 1 = 4 - x

w^{2} - 20 - 2 = 2

x, 2 x + y - 3 z = 5

What is the answer to 1+sqrt(x)=sqrt(1+x^2) ?
The answer to 1+sqrt(x)=sqrt(1+x^2) is x=0,x\approx 2.31459…
Solve for x: 1+sqrt(x)=sqrt(1+x^2)
The solution is x=0,x\approx 2.31459…