What are the solutions to the equation -3=-6x^2+7x ?

The solutions to the equation -3=-6x^2+7x are x=-1/3 ,x= 3/2

Find the zeros of -3=-6x^2+7x

The zeros of -3=-6x^2+7x are x=-1/3 ,x= 3/2

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- 3 = - 6 x^{2} + 7 x

x = - \frac{1}{3}, x = \frac{3}{2}

Solution steps

- 3 = - 6 x^{2} + 7 x

Switch sides

- 6 x^{2} + 7 x = - 3

Move

3

to the left side

- 6 x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 6 ) \cdot 3}{2 ( - 6 )}

7^{2} - 4 (- 6) \cdot 3 = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 ( - 6 )}, x_{2} = \frac{- 7 - 11}{2 ( - 6 )}

x = \frac{- 7 + 11}{2 ( - 6 )} : - \frac{1}{3}

x = \frac{- 7 - 11}{2 ( - 6 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = \frac{3}{2}

3 x y + 6 x - 9 x y^{2}

2 - 9 u < 14 - 6 u

x^{2} + 6 x + 9 = 20

\frac{- 3}{- 1}

- 16 t^{2} + 128 t + 1680 = 0

What are the solutions to the equation -3=-6x^2+7x ?
The solutions to the equation -3=-6x^2+7x are x=-1/3 ,x= 3/2
Find the zeros of -3=-6x^2+7x
The zeros of -3=-6x^2+7x are x=-1/3 ,x= 3/2