What is the answer to sqrt(2x^3+28)=2 ?

The answer to sqrt(2x^3+28)=2 is x=-\sqrt[3]{12}

Solve for x: sqrt(2x^3+28)=2

The solution is x=-\sqrt[3]{12}

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2 x^{3} + 28 = 2

Decimal Notation

x = - 2.28942 \dots

Solution steps

2 x^{3} + 28 = 2

Square both sides:

2 x^{3} + 28 = 4

2 x^{3} + 28 = 4

Solve

Verify Solutions:

True

The solution is

2 x = \frac{x ^{2}}{2}

(k - 1)^{2} + (2 + 1)^{2} = 5

5 x - 4 = 6

8 x + 1 - 5 = 0

\frac{x ^{2} - x - 1}{x - 1} = 1

What is the answer to sqrt(2x^3+28)=2 ?
The answer to sqrt(2x^3+28)=2 is x=-\sqrt[3]{12}
Solve for x: sqrt(2x^3+28)=2
The solution is x=-\sqrt[3]{12}