What are the solutions to the equation 12x^2-120x+200=0 ?

The solutions to the equation 12x^2-120x+200=0 are x=(5(3+sqrt(3)))/3 ,x=(5(3-sqrt(3)))/3

Find the zeros of 12x^2-120x+200=0

The zeros of 12x^2-120x+200=0 are x=(5(3+sqrt(3)))/3 ,x=(5(3-sqrt(3)))/3

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12 x^{2} - 120 x + 200 = 0

x = \frac{5 ( 3 + 3 )}{3}, x = \frac{5 ( 3 - 3 )}{3}

Decimal Notation

x = 7.88675 \dots, x = 2.11324 \dots

Solution steps

12 x^{2} - 120 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 120 ) \pm ( - 120 ) ^{2} - 4 \cdot 12 \cdot 200}{2 \cdot 12}

(- 120)^{2} - 4 \cdot 12 \cdot 200 = 403

x_{1, 2} = \frac{- ( - 120 ) \pm 40 3}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 120 ) + 40 3}{2 \cdot 12}, x_{2} = \frac{- ( - 120 ) - 40 3}{2 \cdot 12}

x = \frac{- ( - 120 ) + 40 3}{2 \cdot 12} : \frac{5 ( 3 + 3 )}{3}

x = \frac{- ( - 120 ) - 40 3}{2 \cdot 12} : \frac{5 ( 3 - 3 )}{3}

The solutions to the quadratic equation are:

x = \frac{5 ( 3 + 3 )}{3}, x = \frac{5 ( 3 - 3 )}{3}

- \frac{2 π}{4}

\frac{28 - 7 b}{b - 4} \cdot \frac{1}{b + 10}

4^{2} + x^{2} = 9^{2}

x - 16 = 9

\frac{x}{3} + \frac{4 x}{5} = \frac{1}{3}

What are the solutions to the equation 12x^2-120x+200=0 ?
The solutions to the equation 12x^2-120x+200=0 are x=(5(3+sqrt(3)))/3 ,x=(5(3-sqrt(3)))/3
Find the zeros of 12x^2-120x+200=0
The zeros of 12x^2-120x+200=0 are x=(5(3+sqrt(3)))/3 ,x=(5(3-sqrt(3)))/3