What is the answer to x-2=sqrt(3x^2+x+1) ?

The answer to x-2=sqrt(3x^2+x+1) is No Solution for x\in\mathbb{R}

Solve for x: x-2=sqrt(3x^2+x+1)

The solution is No Solution for x\in\mathbb{R}

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x - 2 = 3 x^{2} + x + 1

No Solution for x \in R

Solution steps

x - 2 = 3 x^{2} + x + 1

Square both sides:

x^{2} - 4 x + 4 = 3 x^{2} + x + 1

x^{2} - 4 x + 4 = 3 x^{2} + x + 1

Solve

x^{2} - 4 x + 4 = 3 x^{2} + x + 1 : x = - 3, x = \frac{1}{2}

x = - 3, x = \frac{1}{2}

Verify Solutions:

x = - 3

False

, x = \frac{1}{2}

False

The solution is

No Solution for x \in R

k, x = k^{- \frac{1}{3}}

- x^{2} + 2 x + 1 = x

5 x - 6 = 3 x + 4

3 = 3 x - 8 + 1

\frac{x}{x ^{2} + 1} = 0

What is the answer to x-2=sqrt(3x^2+x+1) ?
The answer to x-2=sqrt(3x^2+x+1) is No Solution for x\in\mathbb{R}
Solve for x: x-2=sqrt(3x^2+x+1)
The solution is No Solution for x\in\mathbb{R}