What is the answer to sqrt(k^2-4)=4-k ?

The answer to sqrt(k^2-4)=4-k is k= 5/2

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sqrt(k^2-4)=4-k

k^{2} - 4 = 4 - k

k = \frac{5}{2}

Decimal Notation

k = 2.5

Solution steps

k^{2} - 4 = 4 - k

Square both sides:

k^{2} - 4 = 16 - 8 k + k^{2}

k^{2} - 4 = 16 - 8 k + k^{2}

Solve

k^{2} - 4 = 16 - 8 k + k^{2} : k = \frac{5}{2}

k = \frac{5}{2}

Verify Solutions:

k = \frac{5}{2}

True

The solution is

k = \frac{5}{2}

16 x = 4 x

x - 2 - 7 = - 4

36 - 5 x - x = 0

x^{2} + x - 2 = 2 x - 4

0.5 x = 4 - 3 x + 2