What is the answer to sqrt(x^2+x-2)=2x-4 ?

The answer to sqrt(x^2+x-2)=2x-4 is x=(17+sqrt(73))/6

Solve for x: sqrt(x^2+x-2)=2x-4

The solution is x=(17+sqrt(73))/6

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x^{2} + x - 2 = 2 x - 4

x = \frac{17 + 73}{6}

Decimal Notation

x = 4.25733 \dots

Solution steps

x^{2} + x - 2 = 2 x - 4

Square both sides:

x^{2} + x - 2 = 4 x^{2} - 16 x + 16

x^{2} + x - 2 = 4 x^{2} - 16 x + 16

Solve

x^{2} + x - 2 = 4 x^{2} - 16 x + 16 : x = \frac{17 - 73}{6}, x = \frac{17 + 73}{6}

x = \frac{17 - 73}{6}, x = \frac{17 + 73}{6}

Verify Solutions:

x = \frac{17 - 73}{6}

False

, x = \frac{17 + 73}{6}

True

The solution is

x = \frac{17 + 73}{6}

0.5 x = 4 - 3 x + 2

4 x = \frac{x ^{2}}{4}

2 x + 1 = x + 5

x + 2 x^{2} + x + 9 = 3

What is the answer to sqrt(x^2+x-2)=2x-4 ?
The answer to sqrt(x^2+x-2)=2x-4 is x=(17+sqrt(73))/6
Solve for x: sqrt(x^2+x-2)=2x-4
The solution is x=(17+sqrt(73))/6