What is factor x^{16}-1 ?

The solution to factor x^{16}-1 is (x^8+1)(x^4+1)(x^2+1)(x+1)(x-1)

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factor x^{16}-1

factor

x^{16} - 1

(x^{8} + 1) (x^{4} + 1) (x^{2} + 1) (x + 1) (x - 1)

Solution steps

x^{16} - 1

Apply exponent rules

= (x^{8})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x^{8})^{2} - 1^{2} = (x^{8} + 1) (x^{8} - 1)

= (x^{8} + 1) (x^{8} - 1)

Factor

x^{8} - 1 : (x^{4} + 1) (x^{2} + 1) (x + 1) (x - 1)

= (x^{8} + 1) (x^{4} + 1) (x^{2} + 1) (x + 1) (x - 1)

\frac{7}{2} + 5

- 4 x + 35 > 2 - 4 x + 35 > 2

x^{2} - 140 = - 19

(x^{17})^{\frac{9}{7}}

w^{2} - 4 w + 4

What is factor x^{16}-1 ?
The solution to factor x^{16}-1 is (x^8+1)(x^4+1)(x^2+1)(x+1)(x-1)