What are the solutions to the equation x^2-140=-19 ?

The solutions to the equation x^2-140=-19 are x=11,x=-11

Find the zeros of x^2-140=-19

The zeros of x^2-140=-19 are x=11,x=-11

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x^{2} - 140 = - 19

x = 11, x = - 11

Solution steps

x^{2} - 140 = - 19

Move

140

to the right side

x^{2} = 121

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 121, x = - 121

121 = 11

- 121 = - 11

x = 11, x = - 11

(x^{17})^{\frac{9}{7}}

w^{2} - 4 w + 4

8 x^{2} - 2 x - 3

- x^{2} + 7 x = x^{2} - 5 x

9 x^{2} - 6 x + 82 = 0

What are the solutions to the equation x^2-140=-19 ?
The solutions to the equation x^2-140=-19 are x=11,x=-11
Find the zeros of x^2-140=-19
The zeros of x^2-140=-19 are x=11,x=-11