What are the solutions to the equation -x^2+7x=x^2-5x ?

The solutions to the equation -x^2+7x=x^2-5x are x=0,x=6

Find the zeros of -x^2+7x=x^2-5x

The zeros of -x^2+7x=x^2-5x are x=0,x=6

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- x^{2} + 7 x = x^{2} - 5 x

x = 0, x = 6

Solution steps

- x^{2} + 7 x = x^{2} - 5 x

Move

5 x

to the left side

- x^{2} + 12 x = x^{2}

Move

x^{2}

to the left side

- 2 x^{2} + 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 2^{2} - 4 (- 2) \cdot 0 = 12

x_{1, 2} = \frac{- 12 \pm 12}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 12 + 12}{2 ( - 2 )}, x_{2} = \frac{- 12 - 12}{2 ( - 2 )}

x = \frac{- 12 + 12}{2 ( - 2 )} : 0

x = \frac{- 12 - 12}{2 ( - 2 )} : 6

The solutions to the quadratic equation are:

x = 0, x = 6

9 x^{2} - 6 x + 82 = 0

- 8 x^{5} y^{3} (- 3 x^{3} y^{3})

\frac{10 x - 5 z}{14 x ^{2} + 5 x z - z ^{2}}

\frac{( 2 x ^{2} y ^{2} ) ^{- 3}}{( 2 x ^{2} y ^{2} ) ^{- 4}}

x^{2} + 5 x - 66 = 0

What are the solutions to the equation -x^2+7x=x^2-5x ?
The solutions to the equation -x^2+7x=x^2-5x are x=0,x=6
Find the zeros of -x^2+7x=x^2-5x
The zeros of -x^2+7x=x^2-5x are x=0,x=6