What is the answer to sqrt(2x^2-1)+x=2 ?

The answer to sqrt(2x^2-1)+x=2 is x=-5,x=1

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sqrt(2x^2-1)+x=2

2 x^{2} - 1 + x = 2

x = - 5, x = 1

Solution steps

2 x^{2} - 1 + x = 2

Remove square roots

2 x^{2} - 1 = 4 - 4 x + x^{2}

Solve

2 x^{2} - 1 = 4 - 4 x + x^{2} : x = - 5, x = 1

x = - 5, x = 1

Verify Solutions:

x = - 5

True

, x = 1

True

The solutions are

x = - 5, x = 1

t + 1 = t + 13

4 p^{\frac{2}{3}} = \frac{1}{4}

t - 3 - 2 t + 2 + 2 = 0

What is the answer to sqrt(2x^2-1)+x=2 ?
The answer to sqrt(2x^2-1)+x=2 is x=-5,x=1
Solve for x: sqrt(2x^2-1)+x=2
The solution is x=-5,x=1