What is the answer to sqrt(t-3)-sqrt(2t+2)+2=0 ?

The answer to sqrt(t-3)-sqrt(2t+2)+2=0 is t=7

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sqrt(t-3)-sqrt(2t+2)+2=0

t - 3 - 2 t + 2 + 2 = 0

t = 7

Solution steps

t - 3 - 2 t + 2 + 2 = 0

Remove square roots

t^{2} + 18 t + 81 = 32 t + 32

Solve

t^{2} + 18 t + 81 = 32 t + 32 : t = 7

t = 7

Verify Solutions:

t = 7

True

The solution is

t = 7

5 = (a + 2)^{2} + (- 2 + 5)^{2}

x^{2} = - 1

x - 20 = 0

x^{\frac{3}{5}} = - 64

What is the answer to sqrt(t-3)-sqrt(2t+2)+2=0 ?
The answer to sqrt(t-3)-sqrt(2t+2)+2=0 is t=7
Solve for t: sqrt(t-3)-sqrt(2t+2)+2=0
The solution is t=7