en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sqrt(x+a)=a,a<0

Solution

x + a = a, a < 0

Solution

x = a^{2} - a {a \geq 0}

Solution steps

x + a = a

Square both sides:

x + a = a^{2}

x + a = a^{2}

Solve

x + a = a^{2} : x = a^{2} - a

x = a^{2} - a

Verify Solutions:

x = a^{2} - a {a \geq 0}

The solution is

x = a^{2} - a {a \geq 0}

Popular Examples

solvefor y,x=\sqrt[3]{y}-3 solve for

solvefor y,x=\sqrt[3]{y}+2 solve for

x - 2 = 9 x + 4

6 = 1.5 h

(x - 5)^{\frac{5}{2}} = 32

Frequently Asked Questions (FAQ)

What is the answer to sqrt(x+a)=a,a<0 ?
The answer to sqrt(x+a)=a,a<0 is x=a^2-a {a>= 0}