What is the answer to sqrt(16-x^2)=4-x ?

The answer to sqrt(16-x^2)=4-x is x=4,x=0

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sqrt(16-x^2)=4-x

16 - x^{2} = 4 - x

x = 4, x = 0

Solution steps

16 - x^{2} = 4 - x

Square both sides:

16 - x^{2} = 16 - 8 x + x^{2}

16 - x^{2} = 16 - 8 x + x^{2}

Solve

16 - x^{2} = 16 - 8 x + x^{2} : x = 4, x = 0

x = 4, x = 0

Verify Solutions:

x = 4

True

, x = 0

True

The solutions are

x = 4, x = 0

2 x^{2} + 3 x - 2 = 0

\frac{1}{2} u = u

a (x) = - x + 3

x + x = 2 x - 12

35 + 7 x + 5 x + 34 = 3

What is the answer to sqrt(16-x^2)=4-x ?
The answer to sqrt(16-x^2)=4-x is x=4,x=0
Solve for x: sqrt(16-x^2)=4-x
The solution is x=4,x=0