What is the answer to sqrt(x^2+3x)=2 ?

The answer to sqrt(x^2+3x)=2 is x=1,x=-4

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sqrt(x^2+3x)=2

x^{2} + 3 x = 2

x = 1, x = - 4

Solution steps

x^{2} + 3 x = 2

Square both sides:

x^{2} + 3 x = 4

x^{2} + 3 x = 4

Solve

x^{2} + 3 x = 4 : x = 1, x = - 4

x = 1, x = - 4

Verify Solutions:

x = 1

True

, x = - 4

True

The solutions are

x = 1, x = - 4

x^{\frac{2}{7}} = 2

5 x + 14 = x + 4

(z^{2} - 14 z)^{\frac{4}{5}} = 16

6 t + 8 = 9 t + 3