What are the solutions to the equation 16u^2-40u=-25 ?

The solutions to the equation 16u^2-40u=-25 are u= 5/4

Find the zeros of 16u^2-40u=-25

The zeros of 16u^2-40u=-25 are u= 5/4

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16 u^{2} - 40 u = - 25

u = \frac{5}{4}

Solution steps

16 u^{2} - 40 u = - 25

Move

25

to the left side

16 u^{2} - 40 u + 25 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 16 \cdot 25}{2 \cdot 16}

(- 40)^{2} - 4 \cdot 16 \cdot 25 = 0

u_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 16}

u = \frac{- ( - 40 )}{2 \cdot 16}

\frac{- ( - 40 )}{2 \cdot 16} = \frac{5}{4}

u = \frac{5}{4}

The solution to the quadratic equation is:

u = \frac{5}{4}

1 - 2 x^{2} = 0

3 (7) + 9 (2) < - 18

g^{3} - 3 g^{2} - 2 g + 6

25 a^{2} - 40 a = - 16

\frac{2}{5} x + \frac{4}{5} = - \frac{8}{5}

What are the solutions to the equation 16u^2-40u=-25 ?
The solutions to the equation 16u^2-40u=-25 are u= 5/4
Find the zeros of 16u^2-40u=-25
The zeros of 16u^2-40u=-25 are u= 5/4