What is the answer to 9=n^{2/3} ?

The answer to 9=n^{2/3} is n=sqrt(729),n=-sqrt(729)

Solve for n: 9=n^{2/3}

The solution is n=sqrt(729),n=-sqrt(729)

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9 = n^{\frac{2}{3}}

n = 729, n = - 729

Decimal Notation

n = 27, n = - 27

Solution steps

9 = n^{\frac{2}{3}}

Take both sides of the equation to the power of

3 : 729 = n^{2}

729 = n^{2}

Solve

729 = n^{2} : n = 729, n = - 729

n = 729, n = - 729

Verify Solutions:

n = 729

True

, n = - 729

True

The solutions are

n = 729, n = - 729

x + 10 - x - 6 = 2

3 = 2 x^{2} - 5 x + 39 - x

4 x - 2 - 1 = 2

3 x - 1 = \frac{3 x + 3}{5}

x + 12 - x - 15 = 3

What is the answer to 9=n^{2/3} ?
The answer to 9=n^{2/3} is n=sqrt(729),n=-sqrt(729)
Solve for n: 9=n^{2/3}
The solution is n=sqrt(729),n=-sqrt(729)