What is the answer to 3=sqrt(2x^2-5x+39)-x ?

The answer to 3=sqrt(2x^2-5x+39)-x is x=5,x=6

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3=sqrt(2x^2-5x+39)-x

3 = 2 x^{2} - 5 x + 39 - x

x = 5, x = 6

Solution steps

3 = 2 x^{2} - 5 x + 39 - x

Remove square roots

9 + 6 x + x^{2} = 2 x^{2} - 5 x + 39

Solve

9 + 6 x + x^{2} = 2 x^{2} - 5 x + 39 : x = 5, x = 6

x = 5, x = 6

Verify Solutions:

x = 5

True

, x = 6

True

The solutions are

x = 5, x = 6

4 x - 2 - 1 = 2

3 x - 1 = \frac{3 x + 3}{5}

x + 12 - x - 15 = 3

x + 1 = x + 6 - 1

(x^{2} - 25) 4 - x = 0

What is the answer to 3=sqrt(2x^2-5x+39)-x ?
The answer to 3=sqrt(2x^2-5x+39)-x is x=5,x=6
Solve for x: 3=sqrt(2x^2-5x+39)-x
The solution is x=5,x=6