What is the answer to sqrt(10x)-1=sqrt(2x+11) ?

The answer to sqrt(10x)-1=sqrt(2x+11) is x= 5/2

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sqrt(10x)-1=sqrt(2x+11)

10 x - 1 = 2 x + 11

x = \frac{5}{2}

Decimal Notation

x = 2.5

Solution steps

10 x - 1 = 2 x + 11

Remove square roots

40 x = 64 x^{2} - 160 x + 100

Solve

40 x = 64 x^{2} - 160 x + 100 : x = \frac{5}{2}, x = \frac{5}{8}

x = \frac{5}{2}, x = \frac{5}{8}

Verify Solutions:

x = \frac{5}{2}

True

, x = \frac{5}{8}

False

The solution is

x = \frac{5}{2}

0 = - 4 x + 1 + 12

6 c + 15 = c + 4

(x - 4) = 2 x^{2} - 1

x - 10 = 10 + x

x^{2} - x - 3 = x + 3

What is the answer to sqrt(10x)-1=sqrt(2x+11) ?
The answer to sqrt(10x)-1=sqrt(2x+11) is x= 5/2
Solve for x: sqrt(10x)-1=sqrt(2x+11)
The solution is x= 5/2