What is the answer to \sqrt[3]{4x^2+2x-8}=x ?

The answer to \sqrt[3]{4x^2+2x-8}=x is x=4,x=-sqrt(2),x=sqrt(2)

Solve for x: \sqrt[3]{4x^2+2x-8}=x

The solution is x=4,x=-sqrt(2),x=sqrt(2)

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x = 4, x = - 2, x = 2

Decimal Notation

x = 4, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

Take both sides of the equation to the power of

3 : 4 x^{2} + 2 x - 8 = x^{3}

4 x^{2} + 2 x - 8 = x^{3}

Solve

4 x^{2} + 2 x - 8 = x^{3} : x = 4, x = - 2, x = 2

x = 4, x = - 2, x = 2

Verify Solutions:

x = 4

True

, x = - 2

True

, x = 2

True

The solutions are

x = 4, x = - 2, x = 2

x = x + 13 + 7

8 x = x

7 - 6 x = x

What is the answer to \sqrt[3]{4x^2+2x-8}=x ?
The answer to \sqrt[3]{4x^2+2x-8}=x is x=4,x=-sqrt(2),x=sqrt(2)
Solve for x: \sqrt[3]{4x^2+2x-8}=x
The solution is x=4,x=-sqrt(2),x=sqrt(2)