What is the answer to \sqrt[4]{14x^2-45}=x ?

The answer to \sqrt[4]{14x^2-45}=x is x=3,x=sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\sqrt[4]{14x^2-45}=x

x = 3, x = 5

Decimal Notation

x = 3, x = 2.23606 \dots

Solution steps

Take both sides of the equation to the power of

4 : 14 x^{2} - 45 = x^{4}

14 x^{2} - 45 = x^{4}

Solve

14 x^{2} - 45 = x^{4} : x = 3, x = - 3, x = 5, x = - 5

x = 3, x = - 3, x = 5, x = - 5

Verify Solutions:

x = 3

True

, x = - 3

False

, x = 5

True

, x = - 5

False

The solutions are

x = 3, x = 5

r = r - 7 + 9

x, x + 4 = x

x^{\frac{1}{2}} = x - 2

w, 29 + 4 w = 23 - c w

12 = 3 m + 36 m^{2} + 9

What is the answer to \sqrt[4]{14x^2-45}=x ?
The answer to \sqrt[4]{14x^2-45}=x is x=3,x=sqrt(5)
Solve for x: \sqrt[4]{14x^2-45}=x
The solution is x=3,x=sqrt(5)