What is the answer to 5=sqrt((2+1)^2+(k-1)^2) ?

The answer to 5=sqrt((2+1)^2+(k-1)^2) is k=5,k=-3

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5=sqrt((2+1)^2+(k-1)^2)

5 = (2 + 1)^{2} + (k - 1)^{2}

k = 5, k = - 3

Solution steps

5 = (2 + 1)^{2} + (k - 1)^{2}

Square both sides:

25 = k^{2} - 2 k + 10

25 = k^{2} - 2 k + 10

Solve

25 = k^{2} - 2 k + 10 : k = 5, k = - 3

k = 5, k = - 3

Verify Solutions:

k = 5

True

, k = - 3

True

The solutions are

k = 5, k = - 3

\frac{x ^{3} - 1}{x - 1} = 6.5

2 x + 11 = x + 6

y, x = 5 - 9 - y

2 x = 1

2 x = 4

What is the answer to 5=sqrt((2+1)^2+(k-1)^2) ?
The answer to 5=sqrt((2+1)^2+(k-1)^2) is k=5,k=-3
Solve for k: 5=sqrt((2+1)^2+(k-1)^2)
The solution is k=5,k=-3