What is factor 2y^4+6y^2+5y^2+15 ?

The solution to factor 2y^4+6y^2+5y^2+15 is (2y^2+5)(y^2+3)

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factor 2y^4+6y^2+5y^2+15

factor

2 y^{4} + 6 y^{2} + 5 y^{2} + 15

(2 y^{2} + 5) (y^{2} + 3)

Solution steps

2 y^{4} + 6 y^{2} + 5 y^{2} + 15

Add similar elements:

6 y^{2} + 5 y^{2} = 11 y^{2}

= 2 y^{4} + 11 y^{2} + 15

Let

u = y^{2}

= 2 u^{2} + 11 u + 15

Factor

2 u^{2} + 11 u + 15 : (2 u + 5) (u + 3)

= (2 u + 5) (u + 3)

Substitute back

u = y^{2}

= (2 y^{2} + 5) (y^{2} + 3)

∣ p - 1 ∣ = 4

10 \times 5

3^{3} \cdot 4^{3}

\frac{3}{- 1 + i}

\frac{y - 1}{2} - 2 \leq \frac{3 y - 2}{5}

What is factor 2y^4+6y^2+5y^2+15 ?
The solution to factor 2y^4+6y^2+5y^2+15 is (2y^2+5)(y^2+3)