What is the answer to sqrt(2y+3)=y-1 ?

The answer to sqrt(2y+3)=y-1 is y=2+sqrt(6)

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sqrt(2y+3)=y-1

2 y + 3 = y - 1

y = 2 + 6

Decimal Notation

y = 4.44948 \dots

Solution steps

2 y + 3 = y - 1

Square both sides:

2 y + 3 = y^{2} - 2 y + 1

2 y + 3 = y^{2} - 2 y + 1

Solve

2 y + 3 = y^{2} - 2 y + 1 : y = 2 + 6, y = 2 - 6

y = 2 + 6, y = 2 - 6

Verify Solutions:

y = 2 + 6

True

, y = 2 - 6

False

The solution is

y = 2 + 6

15 = (x + 3)^{2} + (9 - 5)^{2}

47 x - 10.32 x - 5000 = 0

y + 5 = 2 - y - 4

3 x + 96 + 18 = 27

What is the answer to sqrt(2y+3)=y-1 ?
The answer to sqrt(2y+3)=y-1 is y=2+sqrt(6)
Solve for y: sqrt(2y+3)=y-1
The solution is y=2+sqrt(6)