What is the answer to sqrt(2x^2-2)=4 ?

The answer to sqrt(2x^2-2)=4 is x=3,x=-3

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sqrt(2x^2-2)=4

2 x^{2} - 2 = 4

x = 3, x = - 3

Solution steps

2 x^{2} - 2 = 4

Square both sides:

2 x^{2} - 2 = 16

2 x^{2} - 2 = 16

Solve

2 x^{2} - 2 = 16 : x = 3, x = - 3

x = 3, x = - 3

Verify Solutions:

x = 3

True

, x = - 3

True

The solutions are

x = 3, x = - 3

42 + x = x

5 = (3 - x)^{2} + (9 - 5)^{2}

x + 6 - x - 1 = 1

5 - 2 x = - x + 1

x + 3 x - 2 = 4