What is the answer to \sqrt[5]{33-x}+\sqrt[5]{x}=3 ?

The answer to \sqrt[5]{33-x}+\sqrt[5]{x}=3 is x=32,x=1

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\sqrt[5]{33-x}+\sqrt[5]{x}=3

x = 32, x = 1

Solution steps

Rewrite the equation with

and

x = - u^{5} + 33

Solve

u = 1, u = 2

Substitute back

solve for

x

Solve

x = 32, x = 1

Verify Solutions:

x = 32

True

, x = 1

True

The solutions are

x = 32, x = 1

10 = (0 - k)^{2} + (2 k - 0)^{2}

x + 3 + x - 2 = 5

a = x^{2} - 1

- 1 = (- 2)^{2} + (- 2) + c_{1}

What is the answer to \sqrt[5]{33-x}+\sqrt[5]{x}=3 ?
The answer to \sqrt[5]{33-x}+\sqrt[5]{x}=3 is x=32,x=1
Solve for x: \sqrt[5]{33-x}+\sqrt[5]{x}=3
The solution is x=32,x=1