What is the answer to solvefor y,x=sqrt(81-y^2) ?

The answer to solvefor y,x=sqrt(81-y^2) is y=sqrt(-x^2+81) {0<= x<= 9},y=-sqrt(-x^2+81) {0<= x<= 9}

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solvefor y,x=sqrt(81-y^2)

solve for

y, x = 81 - y^{2}

y = - x^{2} + 81 {0 \leq x \leq 9}, y = - - x^{2} + 81 {0 \leq x \leq 9}

Solution steps

x = 81 - y^{2}

Square both sides:

x^{2} = 81 - y^{2}

x^{2} = 81 - y^{2}

Solve

x^{2} = 81 - y^{2} : y = - x^{2} + 81, y = - - x^{2} + 81

y = - x^{2} + 81, y = - - x^{2} + 81

Verify Solutions:

y = - x^{2} + 81 {0 \leq x \leq 9}, y = - - x^{2} + 81 {0 \leq x \leq 9}

The solutions are

y = - x^{2} + 81 {0 \leq x \leq 9}, y = - - x^{2} + 81 {0 \leq x \leq 9}

(x - 1)^{2} - x + 1 = 0

x^{2} = 5 + x

c = 8 W

5 x + 1 = 2 x + 1 + 2

x + 10 - 1 = x

What is the answer to solvefor y,x=sqrt(81-y^2) ?
The answer to solvefor y,x=sqrt(81-y^2) is y=sqrt(-x^2+81) {0<= x<= 9},y=-sqrt(-x^2+81) {0<= x<= 9}