What is the answer to 3x^{4/3}-7=41 ?

The answer to 3x^{4/3}-7=41 is x=8,x=-8

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3x^{4/3}-7=41

3 x^{\frac{4}{3}} - 7 = 41

x = 8, x = - 8

Solution steps

3 x^{\frac{4}{3}} - 7 = 41

Move

7

to the right side

3 x^{\frac{4}{3}} = 48

Divide both sides by

3

x^{\frac{4}{3}} = 16

Take both sides of the equation to the power of

3 : x^{4} = 4096

x^{4} = 4096

Solve

x^{4} = 4096 : x = 8, x = - 8

x = 8, x = - 8

Verify Solutions:

x = 8

True

, x = - 8

True

The solutions are

x = 8, x = - 8

(x - 8)^{\frac{3}{2}} = 8

4 x + 1 - 2 x + 1 + 2 = 0

x - 4 = 2

16 = (12 + 4)^{2} + (x - 2)^{2}