What is the answer to sqrt(2x^2)=1 ?

The answer to sqrt(2x^2)=1 is x= 1/(sqrt(2)),x=-1/(sqrt(2))

Solve for x: sqrt(2x^2)=1

The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))

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2 x^{2} = 1

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

2 x^{2} = 1

Square both sides:

2 x^{2} = 1

2 x^{2} = 1

Solve

2 x^{2} = 1 : x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

, x = - \frac{1}{2}

True

The solutions are

x = \frac{1}{2}, x = - \frac{1}{2}

x, y = 4 - 4 x

y 1 - (1 - y^{2})^{2} = 0

- 3 - 2 x = 9

x, y - 1 = 4 - x^{2}

6 + 8 y = 6 + 8

What is the answer to sqrt(2x^2)=1 ?
The answer to sqrt(2x^2)=1 is x= 1/(sqrt(2)),x=-1/(sqrt(2))
Solve for x: sqrt(2x^2)=1
The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))