What are the solutions to the equation 5m^2-43m+61=5 ?

The solutions to the equation 5m^2-43m+61=5 are m=7,m= 8/5

Find the zeros of 5m^2-43m+61=5

The zeros of 5m^2-43m+61=5 are m=7,m= 8/5

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5 m^{2} - 43 m + 61 = 5

m = 7, m = \frac{8}{5}

Decimal Notation

m = 7, m = 1.6

Solution steps

5 m^{2} - 43 m + 61 = 5

Move

5

to the left side

5 m^{2} - 43 m + 56 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 43 ) \pm ( - 43 ) ^{2} - 4 \cdot 5 \cdot 56}{2 \cdot 5}

(- 43)^{2} - 4 \cdot 5 \cdot 56 = 27

m_{1, 2} = \frac{- ( - 43 ) \pm 27}{2 \cdot 5}

Separate the solutions

m_{1} = \frac{- ( - 43 ) + 27}{2 \cdot 5}, m_{2} = \frac{- ( - 43 ) - 27}{2 \cdot 5}

m = \frac{- ( - 43 ) + 27}{2 \cdot 5} : 7

m = \frac{- ( - 43 ) - 27}{2 \cdot 5} : \frac{8}{5}

The solutions to the quadratic equation are:

m = 7, m = \frac{8}{5}

\frac{1 + 4}{( - 2 \cdot 1 ) - 6}

\frac{1}{7} x^{2} = \frac{3}{7} x

3 x^{2} + 22 x + 24

4 x^{2} - 5 x

x^{2} - 13 x + 12 = 0

What are the solutions to the equation 5m^2-43m+61=5 ?
The solutions to the equation 5m^2-43m+61=5 are m=7,m= 8/5
Find the zeros of 5m^2-43m+61=5
The zeros of 5m^2-43m+61=5 are m=7,m= 8/5