What are the solutions to the equation 1/7 x^2= 3/7 x ?

The solutions to the equation 1/7 x^2= 3/7 x are x=3,x=0

Find the zeros of 1/7 x^2= 3/7 x

The zeros of 1/7 x^2= 3/7 x are x=3,x=0

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\frac{1}{7} x^{2} = \frac{3}{7} x

x = 3, x = 0

Solution steps

\frac{1}{7} x^{2} = \frac{3}{7} x

Multiply both sides by

7

x^{2} = 3 x

Move

3 x

to the left side

x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

x = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

3 x^{2} + 22 x + 24

4 x^{2} - 5 x

x^{2} - 13 x + 12 = 0

\frac{( 2 + i ) ( 4 - 2 i )}{( 1 + i )}

3 x^{2} - 18 x + 27 = 0

What are the solutions to the equation 1/7 x^2= 3/7 x ?
The solutions to the equation 1/7 x^2= 3/7 x are x=3,x=0
Find the zeros of 1/7 x^2= 3/7 x
The zeros of 1/7 x^2= 3/7 x are x=3,x=0