What is the answer to 2sqrt(t)(t)=4t^2 ?

The answer to 2sqrt(t)(t)=4t^2 is t=0,t= 1/4

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2sqrt(t)(t)=4t^2

2 t (t) = 4 t^{2}

t = 0, t = \frac{1}{4}

Decimal Notation

t = 0, t = 0.25

Solution steps

2 t (t) = 4 t^{2}

Move

4 t^{2}

to the left side

2 t t - 4 t^{2} = 0

Factor

2 t t - 4 t^{2} : 2 t (t - 2 t)

2 t (t - 2 t) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0 or t - 2 t = 0

Solve

t - 2 t = 0 : t = \frac{1}{4}, t = 0

t = 0, t = \frac{1}{4}

Verify Solutions:

t = 0

True

, t = \frac{1}{4}

True

The solutions are

t = 0, t = \frac{1}{4}

x - 3 x - 8 = 4

- 2 24 x + 13 = - 11

x^{\frac{5}{2}} = 8 x

3 + 2 t + - 1 + 4 t = 1

2 x - 3 - 4 = 0

What is the answer to 2sqrt(t)(t)=4t^2 ?
The answer to 2sqrt(t)(t)=4t^2 is t=0,t= 1/4
Solve for t: 2sqrt(t)(t)=4t^2
The solution is t=0,t= 1/4