What is the answer to sqrt((x-0)^2+(-x-0)^2)=1 ?

The answer to sqrt((x-0)^2+(-x-0)^2)=1 is x= 1/(sqrt(2)),x=-1/(sqrt(2))

Solve for x: sqrt((x-0)^2+(-x-0)^2)=1

The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))

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(x - 0)^{2} + (- x - 0)^{2} = 1

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

(x - 0)^{2} + (- x - 0)^{2} = 1

Square both sides:

2 x^{2} = 1

2 x^{2} = 1

Solve

2 x^{2} = 1 : x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

, x = - \frac{1}{2}

True

The solutions are

x = \frac{1}{2}, x = - \frac{1}{2}

x^{\frac{3}{2}} = - 125

x, x y = x + 1

- 3 x - 5 = x + 3

x, x y = 2 x

56 - 8 x = 0

What is the answer to sqrt((x-0)^2+(-x-0)^2)=1 ?
The answer to sqrt((x-0)^2+(-x-0)^2)=1 is x= 1/(sqrt(2)),x=-1/(sqrt(2))
Solve for x: sqrt((x-0)^2+(-x-0)^2)=1
The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2))