What is the answer to solvefor x,xy=sqrt(x+1) ?

The answer to solvefor x,xy=sqrt(x+1) is x=(1+sqrt(1+4y^2))/(2y^2),x=(1-sqrt(1+4y^2))/(2y^2)

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solvefor x,xy=sqrt(x+1)

solve for

x, x y = x + 1

x = \frac{1 + 1 + 4 y ^{2}}{2 y ^{2}}, x = \frac{1 - 1 + 4 y ^{2}}{2 y ^{2}}

Solution steps

x y = x + 1

Square both sides:

x^{2} y^{2} = x + 1

x^{2} y^{2} = x + 1

Solve

x^{2} y^{2} = x + 1 : x = \frac{1 + 1 + 4 y ^{2}}{2 y ^{2}}, x = \frac{1 - 1 + 4 y ^{2}}{2 y ^{2}}

x = \frac{1 + 1 + 4 y ^{2}}{2 y ^{2}}, x = \frac{1 - 1 + 4 y ^{2}}{2 y ^{2}}

Verify Solutions:

x = \frac{1 + 1 + 4 y ^{2}}{2 y ^{2}}

True

, x = \frac{1 - 1 + 4 y ^{2}}{2 y ^{2}}

True

The solutions are

x = \frac{1 + 1 + 4 y ^{2}}{2 y ^{2}}, x = \frac{1 - 1 + 4 y ^{2}}{2 y ^{2}}

- 3 x - 5 = x + 3

x, x y = 2 x

56 - 8 x = 0

24 - 4 x = x + 9

What is the answer to solvefor x,xy=sqrt(x+1) ?
The answer to solvefor x,xy=sqrt(x+1) is x=(1+sqrt(1+4y^2))/(2y^2),x=(1-sqrt(1+4y^2))/(2y^2)