What is the answer to \sqrt[4]{x^2-7x}=0 ?

The answer to \sqrt[4]{x^2-7x}=0 is x=7,x=0

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\sqrt[4]{x^2-7x}=0

x = 7, x = 0

Solution steps

Take both sides of the equation to the power of

4 : x^{2} - 7 x = 0

x^{2} - 7 x = 0

Solve

x^{2} - 7 x = 0 : x = 7, x = 0

x = 7, x = 0

Verify Solutions:

x = 7

True

, x = 0

True

The solutions are

x = 7, x = 0

24 - 4 x = x + 9

2 = - \frac{2}{e ^{1}} + c

6 x - 5 = x

7 - x = x - 1

y, x = 4 - y + 1

What is the answer to \sqrt[4]{x^2-7x}=0 ?
The answer to \sqrt[4]{x^2-7x}=0 is x=7,x=0
Solve for x: \sqrt[4]{x^2-7x}=0
The solution is x=7,x=0