What is the answer to 1+sqrt(2-x)-sqrt(5-2x)=0 ?

The answer to 1+sqrt(2-x)-sqrt(5-2x)=0 is x=2,x=-2

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1+sqrt(2-x)-sqrt(5-2x)=0

1 + 2 - x - 5 - 2 x = 0

x = 2, x = - 2

Solution steps

1 + 2 - x - 5 - 2 x = 0

Remove square roots

x^{2} - 8 x + 16 = 20 - 8 x

Solve

x^{2} - 8 x + 16 = 20 - 8 x : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

True

The solutions are

x = 2, x = - 2

- 9 (1 - 8 x)^{\frac{1}{2}} = - 27

- 7 x^{\frac{3}{2}} - 4 = - 60

x - \frac{8}{x} = 2

7^{2} = b^{2} + b^{2}

x^{- \frac{5}{9}} = 3

What is the answer to 1+sqrt(2-x)-sqrt(5-2x)=0 ?
The answer to 1+sqrt(2-x)-sqrt(5-2x)=0 is x=2,x=-2
Solve for x: 1+sqrt(2-x)-sqrt(5-2x)=0
The solution is x=2,x=-2