What is the answer to solvefor x,2=sqrt(x)+y ?

The answer to solvefor x,2=sqrt(x)+y is x=4-4y+y^2 {y<= 2}

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solvefor x,2=sqrt(x)+y

solve for

x, 2 = x + y

x = 4 - 4 y + y^{2} {y \leq 2}

Solution steps

2 = x + y

Switch sides

x + y = 2

Move

y

to the right side

x = 2 - y

Square both sides:

x = 4 - 4 y + y^{2}

x = 4 - 4 y + y^{2}

Verify Solutions:

x = 4 - 4 y + y^{2} {y \leq 2}

The solution is

x = 4 - 4 y + y^{2} {y \leq 2}

x, (x + y)^{3} = 27

(1 - y^{2})^{\frac{1}{2}} = 0

x + 4 - 7 = 0

3 + 6 x - 11 = x

What is the answer to solvefor x,2=sqrt(x)+y ?
The answer to solvefor x,2=sqrt(x)+y is x=4-4y+y^2 {y<= 2}