What are the solutions to the equation 6(2x-4)^2-24=0 ?

The solutions to the equation 6(2x-4)^2-24=0 are x=3,x=1

Find the zeros of 6(2x-4)^2-24=0

The zeros of 6(2x-4)^2-24=0 are x=3,x=1

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6 (2 x - 4)^{2} - 24 = 0

x = 3, x = 1

Solution steps

6 (2 x - 4)^{2} - 24 = 0

Move

24

to the right side

6 (2 x - 4)^{2} = 24

Divide both sides by

6

(2 x - 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 4 = 4 : x = 3

Solve

2 x - 4 = - 4 : x = 1

The solutions to the quadratic equation are:

x = 3, x = 1

5 x^{2} - 4 x = 6

m^{2} - 9 m + 18

4 x^{2} + 7 = 29 x

i^{25}

(2 x + 3) (1 - 3 x) (x - 2) < 0

What are the solutions to the equation 6(2x-4)^2-24=0 ?
The solutions to the equation 6(2x-4)^2-24=0 are x=3,x=1
Find the zeros of 6(2x-4)^2-24=0
The zeros of 6(2x-4)^2-24=0 are x=3,x=1