What is the answer to solvefor y,x=\sqrt[3]{y-2}+8 ?

The answer to solvefor y,x=\sqrt[3]{y-2}+8 is y=x^3-24x^2+192x-510

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solvefor y,x=\sqrt[3]{y-2}+8

solve for

y = x^{3} - 24 x^{2} + 192 x - 510

Solution steps

Switch sides

Move

8

to the right side

Take both sides of the equation to the power of

3 : y - 2 = x^{3} - 24 x^{2} + 192 x - 512

y - 2 = x^{3} - 24 x^{2} + 192 x - 512

Solve

y - 2 = x^{3} - 24 x^{2} + 192 x - 512 : y = x^{3} - 24 x^{2} + 192 x - 510

y = x^{3} - 24 x^{2} + 192 x - 510

Verify Solutions:

y = x^{3} - 24 x^{2} + 192 x - 510

True

The solution is

y = x^{3} - 24 x^{2} + 192 x - 510

x + 1 = 3 x + 2

(2 + 1)^{2} + (k - 1)^{2} = 5

x + 3 + x = x

x^{- \frac{1}{4}} = 2

4 x + 3 = 15

What is the answer to solvefor y,x=\sqrt[3]{y-2}+8 ?
The answer to solvefor y,x=\sqrt[3]{y-2}+8 is y=x^3-24x^2+192x-510