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Popular >

-2x^2+8x<= 0

Solution

- 2 x^{2} + 8 x \leq 0

Solution

x \leq 0 or x \geq 4

+1

Interval Notation

(- \infty, 0] \cup [4, \infty)

Solution steps

- 2 x^{2} + 8 x \leq 0

Rewrite in standard form

- x^{2} + 4 x \leq 0

Factor

- x^{2} + 4 x : - x (x - 4)

- x (x - 4) \leq 0

Multiply both sides by

- 1

(reverse the inequality)

(- x (x - 4)) (- 1) \geq 0 \cdot (- 1)

Simplify

x (x - 4) \geq 0

Identify the intervals

x \leq 0 or x \geq 4

Popular Examples

(125^{(x^2-2)})/(5^x)<= 1/125

\frac{12 5 ^{(x^{2} - 2)}}{5 ^{x}} \leq \frac{1}{125}

-5<= (4-3x)/2 <1

- 5 \leq \frac{4 - 3 x}{2} < 1

simplify 1/2*3 simplify

\frac{1}{2} \cdot 3

26 n - 4 = 360

x - x^{2} = 0

Frequently Asked Questions (FAQ)

What is -2x^2+8x<= 0 ?
The solution to -2x^2+8x<= 0 is x<= 0\lor x>= 4