What is the answer to 16-sqrt(x^2+x^2)=0 ?

The answer to 16-sqrt(x^2+x^2)=0 is x=8sqrt(2),x=-8sqrt(2)

Solve for x: 16-sqrt(x^2+x^2)=0

The solution is x=8sqrt(2),x=-8sqrt(2)

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16 - x^{2} + x^{2} = 0

x = 82, x = - 82

Decimal Notation

x = 11.31370 \dots, x = - 11.31370 \dots

Solution steps

16 - x^{2} + x^{2} = 0

Move

16

to the right side

- x^{2} + x^{2} = - 16

Square both sides:

2 x^{2} = 256

2 x^{2} = 256

Solve

2 x^{2} = 256 : x = 82, x = - 82

x = 82, x = - 82

Verify Solutions:

x = 82

True

, x = - 82

True

The solutions are

x = 82, x = - 82

(x - 3)^{2} + (- 1 - 2)^{2} = 4

7 x + 4 = 5

\frac{x - 1}{x + 1} = 1

x^{2} - 17 - 8 = 0

x, y = 2 x - 1

What is the answer to 16-sqrt(x^2+x^2)=0 ?
The answer to 16-sqrt(x^2+x^2)=0 is x=8sqrt(2),x=-8sqrt(2)
Solve for x: 16-sqrt(x^2+x^2)=0
The solution is x=8sqrt(2),x=-8sqrt(2)