What is the answer to (\sqrt[3]{x-6})^2=9 ?

The answer to (\sqrt[3]{x-6})^2=9 is x=-21,x=33

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(\sqrt[3]{x-6})^2=9

x = - 21, x = 33

Solution steps

Move

9

to the left side

Factor

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x = - 21, x = 33

Verify Solutions:

x = - 21

True

, x = 33

True

The solutions are

x = - 21, x = 33

\frac{x + 26}{x + 1} = 12

6 x - 400 - 5 x (x - 4) = 0

2 x^{2} + x - 1 - x = 5 - 2 x

2 x + 3 - x + 2 = 0

(x - 5)^{\frac{2}{3}} = 8

What is the answer to (\sqrt[3]{x-6})^2=9 ?
The answer to (\sqrt[3]{x-6})^2=9 is x=-21,x=33
Solve for x: (\sqrt[3]{x-6})^2=9
The solution is x=-21,x=33