What is the answer to sqrt(2x^2+x-1)-x=5-2x ?

The answer to sqrt(2x^2+x-1)-x=5-2x is x=2,x=-13

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sqrt(2x^2+x-1)-x=5-2x

2 x^{2} + x - 1 - x = 5 - 2 x

x = 2, x = - 13

Solution steps

2 x^{2} + x - 1 - x = 5 - 2 x

Remove square roots

2 x^{2} + x - 1 = 25 - 10 x + x^{2}

Solve

2 x^{2} + x - 1 = 25 - 10 x + x^{2} : x = 2, x = - 13

x = 2, x = - 13

Verify Solutions:

x = 2

True

, x = - 13

True

The solutions are

x = 2, x = - 13

2 x + 3 - x + 2 = 0

(x - 5)^{\frac{2}{3}} = 8

6 x = 3

20 - n = \frac{n}{4}

x^{2} + 1 = 4

What is the answer to sqrt(2x^2+x-1)-x=5-2x ?
The answer to sqrt(2x^2+x-1)-x=5-2x is x=2,x=-13
Solve for x: sqrt(2x^2+x-1)-x=5-2x
The solution is x=2,x=-13